помогитееее!!!!!!!!!!!!!!!!!!!. Created by sagdianazorobaeva28. algebra-ru

помогитееее!!!!!!!!!!!!!!!!!!!...

bena20193

Объяснение:

$c=6\ \ \ \ b=4\\a=\sqrt{c^2-b^2}=\sqrt{6^2-4^2}=\sqrt{36-16}=\sqrt{20}=2\sqrt{5}.\\sin\alpha =\frac{a}{c}=\frac{2\sqrt{5} }{6}=\frac{\sqrt{5} }{3} .\\cos\alpha =\frac{b}{c}=\frac{4}{6}=\frac{2}{3}.\\tg\alpha =\frac{a}{b} =\frac{2\sqrt{5} }{4} =\frac{\sqrt{5} }{2}.\\ctg\alpha =\frac{b}{a}=\frac{4}{2\sqrt{5} }=\frac{2}{\sqrt{5} }=\frac{2\sqrt{5} }{5} .$

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sangers1959

Verified answer

Ответ:

Объяснение:

по теореме Пифагора

a=√(c²-b²)=√(36-16)=√20=2√5

sinα=a/c=2√5/6=√5/3

cosα=b/c=4/6=2/3

tgα=a/b=2√5/4=√5/2

ctgα=b/a=4/2√5=2/√5

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