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7vadimka
@7vadimka
August 2021
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помогите,пожалуиста!!)))
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Angell0k
Verified answer
А)...=(3a^2+3b^2-2a^2-2ab-2b^2)/(3a^3-3b^3)=(a^2-2ab-b^2)/3(a^3-b^3)=(a-b)^2/3(a-b)(a^2+ab+b^2)=(a-b)/3(a^2+ab+b^2)
б)...=(2m^2-m^2-mn+n^2+mn)/(m^3+n^3)=(m^2+n^2)/(m^3+n^3)
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7vadimka
я не понимаю что здесь написано!
Angell0k
а ответ хоия бы понимаешь?
7vadimka
да
7vadimka
но спасибо ,на этом
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Answers & Comments
Verified answer
А)...=(3a^2+3b^2-2a^2-2ab-2b^2)/(3a^3-3b^3)=(a^2-2ab-b^2)/3(a^3-b^3)=(a-b)^2/3(a-b)(a^2+ab+b^2)=(a-b)/3(a^2+ab+b^2)б)...=(2m^2-m^2-mn+n^2+mn)/(m^3+n^3)=(m^2+n^2)/(m^3+n^3)