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Розалита12
@Розалита12
July 2022
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Помогите,пожалуйста) Логарифмы
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Ilyasssssss
A)log(2)2^3=3*log(2)2=3*1=3
б)log(5)5^7=7*log(5)5=7*1=7
в)log(9)9^1999=1999*log(9)9=1999*1=1999
г)2^(log(2)5)=5^(log(2)2)=5^1=5
д)3^(log(3)90)=90^(log(3)3)=90^1=90
е)5^(log(5)1/2)=(1/2)^(log(5)5)=(1/2)^1=1/2
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Answers & Comments
б)log(5)5^7=7*log(5)5=7*1=7
в)log(9)9^1999=1999*log(9)9=1999*1=1999
г)2^(log(2)5)=5^(log(2)2)=5^1=5
д)3^(log(3)90)=90^(log(3)3)=90^1=90
е)5^(log(5)1/2)=(1/2)^(log(5)5)=(1/2)^1=1/2