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svetusvet
@svetusvet
August 2021
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помогите,пожалуйста с С1
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Nucleus
2sin^2(x)=sqrt(3)*sinx
2sin^2(x)-sqrt(3)*sinx=0
sinx(2sinx-sqrt(3))=0
sinx=0 или 2sinx=sqrt(3), => sinx=√3/2
x=πn; x=π/3+2πn; x=2π/3+2πn
n∈z
x∈[-3π;-3π/2]
x=-3π;-2π;-5π/3.
2 votes
Thanks 1
Nucleus
Помог? Поставьте как лучшее)))
svetusvet
конечно:)хорошо
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Answers & Comments
2sin^2(x)-sqrt(3)*sinx=0
sinx(2sinx-sqrt(3))=0
sinx=0 или 2sinx=sqrt(3), => sinx=√3/2
x=πn; x=π/3+2πn; x=2π/3+2πn
n∈z
x∈[-3π;-3π/2]
x=-3π;-2π;-5π/3.