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HaCTeHaaa
@HaCTeHaaa
July 2022
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Помогите,пожалуйста,с тригонометрией) (25 баллов)
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sedinalana
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3sin²3x-2√3sin3xcos3x-5cos²3x-2sin²3x-2cos²3x=0/cos²3x
tg²3x-2√3tg3x-7=0
tg3x=a
a²-2√3a-7=0
D=12+28=40
a1=(2√3-2√10)/2=√3-√10⇒tgx=√3-√10⇒x=arctg(√3-√10)+πn,n∈z
a2=√3+√10⇒tgx=√3+√10⇒x=arctg(√3+√10)+πn,n∈z
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Answers & Comments
Verified answer
3sin²3x-2√3sin3xcos3x-5cos²3x-2sin²3x-2cos²3x=0/cos²3xtg²3x-2√3tg3x-7=0
tg3x=a
a²-2√3a-7=0
D=12+28=40
a1=(2√3-2√10)/2=√3-√10⇒tgx=√3-√10⇒x=arctg(√3-√10)+πn,n∈z
a2=√3+√10⇒tgx=√3+√10⇒x=arctg(√3+√10)+πn,n∈z