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nadirabaratova
@nadirabaratova
July 2022
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Помогите решить уравнение разности квадратов :
1)81х^2-9=0 ;2)0.04x^3-16x=0
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mmb1
Verified answer
1)81х^2-9=0
(9x-3)(9x+3)=0
x=1/3
x=-1/3
;2)0.04x^3-16x=0
x(0.2x-4)(0.2x+4)=0
x=0
x=8
x=-8
1 votes
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Answers & Comments
Verified answer
1)81х^2-9=0(9x-3)(9x+3)=0
x=1/3
x=-1/3
;2)0.04x^3-16x=0
x(0.2x-4)(0.2x+4)=0
x=0
x=8
x=-8