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fdedcvggre
@fdedcvggre
July 2022
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Помогите!!!Zn^3(po^4)^2 относит. мол. масса
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Chemicalfoxbrush
Mr=M
Mr(Zn3(PO4)2)=65*3+31*2+16*4*2=195+62+128=385
2 votes
Thanks 1
Alexei78
M(Zn3(PO4)2)=65*3+(31+16*4)*2=385 g/mol
2 votes
Thanks 1
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Answers & Comments
Mr(Zn3(PO4)2)=65*3+31*2+16*4*2=195+62+128=385