Ответ:
1. w(Fe)=M(Fe)/M(FeO)=56/72≈0.78≈78%
w(Fe)=M(Fe)*2/M(Fe2O3)=56*2/160=0.7=70%
w(Fe)=M(Fe)*3/M(Fe3O4)=56*3/232≈0.724≈72.4%
2. H2SO4: w(H) = 2* 1/2+ 32+ 16*4 = 0.02* 100% = 20%.
w(S) = 32/ 98 = 0.33 * 100% = 33%.
w(O) = 4* 16/ 98 = 0.65 * 100% = 65%.
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Answers & Comments
Ответ:
1. w(Fe)=M(Fe)/M(FeO)=56/72≈0.78≈78%
w(Fe)=M(Fe)*2/M(Fe2O3)=56*2/160=0.7=70%
w(Fe)=M(Fe)*3/M(Fe3O4)=56*3/232≈0.724≈72.4%
2. H2SO4: w(H) = 2* 1/2+ 32+ 16*4 = 0.02* 100% = 20%.
w(S) = 32/ 98 = 0.33 * 100% = 33%.
w(O) = 4* 16/ 98 = 0.65 * 100% = 65%.