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duhgjkg
@duhgjkg
August 2022
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ПОСЛЕДОВАТЕЛЬНОСТЬ an геометрическая прогрессия. найдите s6,если a1=0,2 q=2
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Cофи12398817
S(n)=(a1*(q^n - 1))/(q-1)
Следовательно
S(6) = (0,2*(2^6 - 1))/(2-1)
S(6) = 12,6/1 = 12,6
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Answers & Comments
Следовательно
S(6) = (0,2*(2^6 - 1))/(2-1)
S(6) = 12,6/1 = 12,6