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marinka31
@marinka31
December 2021
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Построить график функции модуль
Ix+2I разделить на 4-х в квадрате
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Гоша68
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1. x>=-2 y=(x+2)/(2-x)(2+x)=1/(2-x)
2. x<-2 y=-(x+2)/(2-x)(2+x)=-1/(2-x)=1/(x-2)
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Answers & Comments
Verified answer
1. x>=-2 y=(x+2)/(2-x)(2+x)=1/(2-x)2. x<-2 y=-(x+2)/(2-x)(2+x)=-1/(2-x)=1/(x-2)