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yana00798
@yana00798
July 2022
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Постройте график функции
y= -2sin x + 1
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allegefickt
Y = -2sinx + 1
sinx определен только на промежутке [-1;1]
тогда
x = - 1
y = -2(-1) + 1 = 2 + 1 = 3
x = 0
y = -2*0 + 1 = 1
x = 1
y = -2*1 + 1 = -2 + 1 = - 1
Строим график
y |
|
|
------------------------ > x
x = - 1 y = 3
x = 0 y = 1
x = 1 y = - 1
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Answers & Comments
sinx определен только на промежутке [-1;1]
тогда
x = - 1
y = -2(-1) + 1 = 2 + 1 = 3
x = 0
y = -2*0 + 1 = 1
x = 1
y = -2*1 + 1 = -2 + 1 = - 1
Строим график
y |
|
|
------------------------ > x
x = - 1 y = 3
x = 0 y = 1
x = 1 y = - 1