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ivanovaanastasia9
@ivanovaanastasia9
August 2022
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Постройте график уравнения (x^2+y^2+6y)(x-y)=0
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vadimzhilin
1)x²+y²+6y=0
x²+(y+3)²=9 окружность с центром (0;-3) и радиусом 3
2)х-у=0
у=х биссектриса 1 и 3 координатных углов
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vadimzhilin
норм(
vadimzhilin
норм??
ivanovaanastasia9
а откуда 9 взялось??
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Answers & Comments
x²+(y+3)²=9 окружность с центром (0;-3) и радиусом 3
2)х-у=0
у=х биссектриса 1 и 3 координатных углов