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temnikova1
@temnikova1
July 2022
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пожалуйста 2 задание )
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selmash21
А)
м/3н^3=3м^2н/9мн^4
б)
=3(х-у)/(х+у)(х-у)=3(х-у)/(х^2-у^2)
в)
=м/2(м+н)=м(м+н)/2(м+н)(м+н)=
=м(м+н)/(2м^2+4мн+2н^2)
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Answers & Comments
м/3н^3=3м^2н/9мн^4
б)
=3(х-у)/(х+у)(х-у)=3(х-у)/(х^2-у^2)
в)
=м/2(м+н)=м(м+н)/2(м+н)(м+н)=
=м(м+н)/(2м^2+4мн+2н^2)