Пожалуйста, нужно решить 3 и 4. Created by Dadala. algebra-ru

Пожалуйста, нужно решить 3 и 4...

hjkgnkgjnbkjfbgkf 3a. $(3 x^{2} y)^{2}= 9 x^{4}y^{2}$
3б. $2*b^{2}*(-a^{2}*b )^{3}=-2*b^{2}*a^{6}*b^{3}=-2*a^{6}*b^{5}$

4a. $12 x^{7}y^{4} =4 x^{6} y^{2} *(3xy^{2})$
4б. $(\±6ab^{3})^{2} =36a^{2}b^{6}$

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fadarm

Verified answer

3)(3 x^2 y)^2=6 x^{2} +2y
2b^{2} (-a^{2} b)^{3} = 2b^2-3a^2*3b=2b^2-6a^2b

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