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kpaz19
@kpaz19
July 2022
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Пожалуйста очень надо.
их сделать 1, 2, 4.
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Simba2017
4)В проекции найти высоту BH1 надо
AC=17
AB1=9
B1C=10
BH1=2S/AC=2S/17
p=(17+10+9)/2=18
S(AB1C)=√(18*(18-17)(18-10)(18-9))=36
BH1=2*36/17=72/17
ΔBB1H-прямоугольный
BH=BH1/cos30=(72/17)/(√3/2)=48√3/17
S(ABC)=AC*BH/2=17*(48√3/17)/2=24√3≈41.56
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Answers & Comments
AC=17
AB1=9
B1C=10
BH1=2S/AC=2S/17
p=(17+10+9)/2=18
S(AB1C)=√(18*(18-17)(18-10)(18-9))=36
BH1=2*36/17=72/17
ΔBB1H-прямоугольный
BH=BH1/cos30=(72/17)/(√3/2)=48√3/17
S(ABC)=AC*BH/2=17*(48√3/17)/2=24√3≈41.56