CO2 + Ba(OH)2 = BaCO3 + H2O
n(BaCO3) = 19.7/197 = 0.1 моль
n(CO2) = 0.1 моль
V(CO2) = 0.1*22.4 = 2.24 л
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CO2 + Ba(OH)2 = BaCO3 + H2O
n(BaCO3) = 19.7/197 = 0.1 моль
n(CO2) = 0.1 моль
V(CO2) = 0.1*22.4 = 2.24 л