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gulmerey97
@gulmerey97
September 2021
1
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Пожалуйста помогите
0,5sin40-cos30+cos20cos10
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nafanya2014
Verified answer
cos20°cos10°=(1/2)( cos(20°+10°)·cos(20°-10°))= (1/2)cos30°+(1/2)cos10°
Тогда
0,5·sin40°-cos30°+ cos20°·cos10°=
=
0,5·sin40°-cos30° +
(1/2)cos30°+(1/2)cos10°
=
0,5·sin40°+0,5сos10°-0,5cos30°=
=0,5sin40°+0,5·(cos10°-cos30°)=
=
0,5sin40°+0,5·2sin((10°+30°)/2)sin((30°-10°)/2)
=0,5·2sin20°cos20°+sin20°·sin10°=
=sin20°·(cos20°+sin10°)
2 votes
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Answers & Comments
Verified answer
cos20°cos10°=(1/2)( cos(20°+10°)·cos(20°-10°))= (1/2)cos30°+(1/2)cos10°Тогда
0,5·sin40°-cos30°+ cos20°·cos10°=
=0,5·sin40°-cos30° +(1/2)cos30°+(1/2)cos10°
=0,5·sin40°+0,5сos10°-0,5cos30°=
=0,5sin40°+0,5·(cos10°-cos30°)=
=0,5sin40°+0,5·2sin((10°+30°)/2)sin((30°-10°)/2)
=0,5·2sin20°cos20°+sin20°·sin10°=
=sin20°·(cos20°+sin10°)