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r2999
@r2999
August 2022
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Пожалуйста помогите))
109. Найдите координаты начала С вектора CD (-2;4;3), если его конец D(3;-2;3).
110. Найдите длины векторов m (3;2;1) и n (-2;-1;6)
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oganesbagoyan
Verified answer
109)
-2=Xd-Xc ==>-2=3-Xc ==>Xc=5
4=Yd-Yc ==>4=-2-yc ==>yc=-6
3=Zd-Zc ==>3=3-Zc ==>Zc=0
C(5;-6;0)
110)
m=sqrt(3^2+2^2+1^2)=sqrt14 [
m= √14
]
n=sqrt((-2)²+(-1)²+6²)=sqrt41 [
n= √41
]
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Answers & Comments
Verified answer
109) -2=Xd-Xc ==>-2=3-Xc ==>Xc=54=Yd-Yc ==>4=-2-yc ==>yc=-6
3=Zd-Zc ==>3=3-Zc ==>Zc=0
C(5;-6;0)
110) m=sqrt(3^2+2^2+1^2)=sqrt14 [ m= √14 ]
n=sqrt((-2)²+(-1)²+6²)=sqrt41 [ n= √41]