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zarujan01
@zarujan01
September 2021
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пожалуйста помогите номер 454 5 класс даю 35 баллов
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Сашуня5
А) угол EOF развернутый 180°
180-40 = 140°
б) 40 + 50 + 20=110°-DOF
1 votes
Thanks 0
isom
А)∠DOF=180°-∠EOD=180°-40°=140°
б) 40°+20°+50°=110°
0 votes
Thanks 0
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Answers & Comments
180-40 = 140°
б) 40 + 50 + 20=110°-DOF
б) 40°+20°+50°=110°