1) 3x(3x-8)=20
9x^2-24x=20
(3x+2)(3x-10)=0
3x+2=0
3x-10=0
x1= -2/3
x2= 10/3
2)(2x-3)^2=8x
4x^2-20x+9=0
(2x-1)(2x-9)=0
2x-1=0
2x-9=0
x1=1/2
x2=9/2
3)(2x+4)^2=11x^2+1
7x^2-16x-15=0
(7x+5)(x-3)=0
x1= -5/7
x2= 3
4)4x^2-19x+12=0
4x^2 =7
x1= -√7/2
x2=√7/2
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Answers & Comments
1) 3x(3x-8)=20
9x^2-24x=20
(3x+2)(3x-10)=0
3x+2=0
3x-10=0
x1= -2/3
x2= 10/3
2)(2x-3)^2=8x
4x^2-20x+9=0
(2x-1)(2x-9)=0
2x-1=0
2x-9=0
x1=1/2
x2=9/2
3)(2x+4)^2=11x^2+1
7x^2-16x-15=0
(7x+5)(x-3)=0
x1= -5/7
x2= 3
4)4x^2-19x+12=0
4x^2 =7
x1= -√7/2
x2=√7/2