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GrosserKater
@GrosserKater
July 2022
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Пожалуйста помогите решить! Трегонометрическое уравнение:
2Cos^2x-2cosx-1=0
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redorian41
Замена переменной
cosx=t
2t^2-2t-1=0
D=4+8=12 (√12) D>0
x1=(2+√12)/4=
√3/2
x2=(2-
√12)/4= (2-2√3)/4=-
√3/2
cosx=
√3/2 и cosx=-
√3/2
x1=+/-pi/6+2pin x2=-5pi/6+2pin
1 votes
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Answers & Comments
cosx=t
2t^2-2t-1=0
D=4+8=12 (√12) D>0
x1=(2+√12)/4=√3/2
x2=(2-√12)/4= (2-2√3)/4=-√3/2
cosx=√3/2 и cosx=-√3/2
x1=+/-pi/6+2pin x2=-5pi/6+2pin