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romanenkooleg99
@romanenkooleg99
August 2022
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evvoronina1
Sin(a)=3/5
sin(2a)=?
sin(2a)=2sin(a)•cos(a)
Так как sin^2(a)+cos^2(a)=1
cos(a)=√[(1-sin^2(a)]
sin(2a)=2sin(a)•√[(1-sina^2(a)]
sin(2a)+ 2 • 3/5 • √[1 - (3/5)^2] = 6/5 • √(1 - 9/25) =
=6/5 • √(25/25 - 9/25) = 6/5 • √16/25 = 6/5 • 4/5 = 24/25
Ответ: 24/25
1 votes
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Answers & Comments
sin(2a)=?
sin(2a)=2sin(a)•cos(a)
Так как sin^2(a)+cos^2(a)=1
cos(a)=√[(1-sin^2(a)]
sin(2a)=2sin(a)•√[(1-sina^2(a)]
sin(2a)+ 2 • 3/5 • √[1 - (3/5)^2] = 6/5 • √(1 - 9/25) =
=6/5 • √(25/25 - 9/25) = 6/5 • √16/25 = 6/5 • 4/5 = 24/25
Ответ: 24/25