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Yuzuki
@Yuzuki
August 2021
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Пожалуйста, помогите решить!!!!!!!!!!!!!
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Universalka
Verified answer
Обозначим log₃x = m, тогда ОДЗ: x > 0
6/m - m - 1 = 0
6 - m² - m = 0
m² + m - 6 = 0
m₁ = - 3 m₂ = 2 - по теореме, обратной теореме Виетта
log₃x = - 3 log₃x = 2
x₁ = 3⁻³ = 1/27 x₂ = 3² = 9
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Yuzuki
Спасибо)))))
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Answers & Comments
Verified answer
Обозначим log₃x = m, тогда ОДЗ: x > 06/m - m - 1 = 0
6 - m² - m = 0
m² + m - 6 = 0
m₁ = - 3 m₂ = 2 - по теореме, обратной теореме Виетта
log₃x = - 3 log₃x = 2
x₁ = 3⁻³ = 1/27 x₂ = 3² = 9