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Summ6r
@Summ6r
March 2022
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Пожалуйста помогите решить.....
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nKrynka
Решение
1) (b - b⁻¹/²) / (1 - b⁻¹/²) = (b - 1/b¹/²) / (1 - b¹/²) = (b³/² - 1) / (b¹/² - 1) =
= [(b¹/²)³ - 1] / (b¹/² - 1) = [(b¹/² - 1) * (b + b¹/² + 1)] / (b¹/² - 1) =
= b + b¹/² + 1
2) (b + b⁻¹/²) / (1 + b⁻¹/²) = (b + 1/b¹/²) / (1 + b¹/²) = (b³/² + 1) / (b¹/² + 1) =
= [(b¹/²)³ + 1] / (b¹/² + 1) = [(b¹/² + 1) * (b - b¹/² + 1)] / (b¹/² + 1) =
= b - b¹/² + 1
3) b + b¹/² + 1 - b + b¹/² - 1 = 2*b¹/²
4) 2b¹/² * (b⁻¹/² / 2) + 7 = 1 + 7 = 8
5) 8¹/³ = (2³)¹/³ = 2
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Answers & Comments
1) (b - b⁻¹/²) / (1 - b⁻¹/²) = (b - 1/b¹/²) / (1 - b¹/²) = (b³/² - 1) / (b¹/² - 1) =
= [(b¹/²)³ - 1] / (b¹/² - 1) = [(b¹/² - 1) * (b + b¹/² + 1)] / (b¹/² - 1) =
= b + b¹/² + 1
2) (b + b⁻¹/²) / (1 + b⁻¹/²) = (b + 1/b¹/²) / (1 + b¹/²) = (b³/² + 1) / (b¹/² + 1) =
= [(b¹/²)³ + 1] / (b¹/² + 1) = [(b¹/² + 1) * (b - b¹/² + 1)] / (b¹/² + 1) =
= b - b¹/² + 1
3) b + b¹/² + 1 - b + b¹/² - 1 = 2*b¹/²
4) 2b¹/² * (b⁻¹/² / 2) + 7 = 1 + 7 = 8
5) 8¹/³ = (2³)¹/³ = 2