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tonitalent
@tonitalent
August 2021
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Lesben
X(xˇ2+4x+4)=3(x+2)
x(x+2)ˇ2-3(x+2)=0
(x+2)(xˇ2+2x-3)=0
(x+2)(x+3)(x-1)=0
x1=-2,x2=-3,x3=1
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Answers & Comments
x(x+2)ˇ2-3(x+2)=0
(x+2)(xˇ2+2x-3)=0
(x+2)(x+3)(x-1)=0
x1=-2,x2=-3,x3=1