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Shymside27
@Shymside27
July 2022
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Пожалуйста помогите с 2 и 3
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jelsomina
2a)tgactga-sin2a=1-sin2a=cos2a
б)cos2a-1/cos2a= -sin2a/cos2a= -tg2a
3а) (1+tg2a)cos4a+sin2a=1
1/cos2a×cos4a+sin2a=1
cos2a+sin2a=1
1=1
б)1-sin2a/sinacosa×tga=1
cos2a/sinacosa×tga=1
cosa/sina×tga=1
cosa/sina×sina/cosa=1
1=1
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Thanks 1
Shymside27
Спасибо большое❤️❤️❤️
jelsomina
Пожалуйста)
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Answers & Comments
б)cos2a-1/cos2a= -sin2a/cos2a= -tg2a
3а) (1+tg2a)cos4a+sin2a=1
1/cos2a×cos4a+sin2a=1
cos2a+sin2a=1
1=1
б)1-sin2a/sinacosa×tga=1
cos2a/sinacosa×tga=1
cosa/sina×tga=1
cosa/sina×sina/cosa=1
1=1