А) 12m⁴/k³ × k⁶/9m²= 4m²×k³/3=4k³m²/3
Б) 3х²/16-у²÷15х⁵/4+у=
= 3х²/(4-у)×(4+у) × 4+у/15х⁵= 1/4-у × 1/5х³ =
= 1/5х³×(4-у) = 1/20х³-5х³у
В) x²-1/x²-4 ×5x+10/x+1 =
=(x-1) × (x+1)/(x-2)×(x+2)×5(x+2)/x+1= x-1/x-2×5= 5(x-1)/x-2 = 5x-5/x-2
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
А) 12m⁴/k³ × k⁶/9m²= 4m²×k³/3=4k³m²/3
Б) 3х²/16-у²÷15х⁵/4+у=
= 3х²/(4-у)×(4+у) × 4+у/15х⁵= 1/4-у × 1/5х³ =
= 1/5х³×(4-у) = 1/20х³-5х³у
В) x²-1/x²-4 ×5x+10/x+1 =
=(x-1) × (x+1)/(x-2)×(x+2)×5(x+2)/x+1= x-1/x-2×5= 5(x-1)/x-2 = 5x-5/x-2