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1036
@1036
September 2021
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Пожалуйста, помогите с производными
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m11m
А) f(x) =
2x-3
x+1
f(x)' =
(2x-3)' (x+1) - (2x-3) (x+1)'
=
2(x+1) - (2x-3)
=
2x+2-2x+3
=
5
(x+1)² (x+1)² (x+1)² (x+1)²
г) f(x)=√(4x-2)
f(x)' =
1
* (4x-2)' =
4
=
2
2√(4x-2) 2√(4x-2) √(4x-2)
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Answers & Comments
x+1
f(x)' = (2x-3)' (x+1) - (2x-3) (x+1)' = 2(x+1) - (2x-3) = 2x+2-2x+3 = 5
(x+1)² (x+1)² (x+1)² (x+1)²
г) f(x)=√(4x-2)
f(x)' = 1 * (4x-2)' = 4 = 2
2√(4x-2) 2√(4x-2) √(4x-2)