Пожалуйста, помогите с решением
1) 3^log3(основание) 4+1 =
2) 3^log3(основание) 5-3 =
1) 3^log3(основание) 4+1 =
2) 3^log3(основание) 5-3 =
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Основное логарифмическое тождествоa ^(loga b) = b
3^(log3 4 + 1) = 3^(log3 4) * 3^1 = 4 * 3 = 12
3^(log3 5 - 3) = 3^(log3 5) * 1/3^3 = 5 /27
a ^(loga b) = b
3^(log3 4 + 1) = 3^(log3 4) * 3^1 = 4 * 3 = 12
3^(log3 5 - 3) = 3^(log3 5) * 1/3^3 = 5 /27