пожалуйста помогите! срочно надо! сократите дробь:. Created by osedko. algebra-ru

1) x1=; x2= -32) x1=4; x2= -33)

пожалуйста помогите! срочно надо! сократите дробь:...

osedko @osedko

July 2022 2 3 Report

пожалуйста помогите! срочно надо!

сократите дробь:

appleseen

Verified answer

1) $3 x^{2} +7x-6; D= 7^{2} -4*3*(-6)=49+72=121$
x1= $\frac{2}{3}$ ; x2= -3
2) $x^{2} -x-12;$ x1=4; x2= -3
3) $\frac{3 x^{2} +7x-6}{ x^{2} -x-12} = \frac{3(x- \frac{2}{3})(x+3) }{(x-4)(x+3)} = \frac{3x-2}{x-4}$

1 votes Thanks 0

ТатМих

Verified answer

3х²+7х-6=0
D=49+72=121
√D=11
x1=(-7+11)/6=4/6=2/3
x2=(-7-11)/6=-3

3(x-2/3)(x+3)

x²-x-12=0
D=1+48=49
√49=7
x1=(1-7)/2=-3
x2=(1+7)/2=4

(x+3)(x-4)

3(x-2/3)(x+3) / (x+3)(x-4)=3(x-2/3) / (x-4)=(3x-2) / (x-4)

2 votes Thanks 1

Answers & Comments

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