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брсэомэо
@брсэомэо
August 2021
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пожалуйста помогите срочно!!!!!
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oganesbagoyan
Verified answer
1.
S_бок =(2πR)*H =(2*π*8 дм)*7 дм =112 π дм
².
========
2.
d =
√ ( (2R)² +H² ) =√ ( (2*3)² +4² ) = √ ( 6² +4² ) = √ ( 36 +16 ) =√ 52 =√(4*13) =2√13 (м)
.
* * * !
если бы
диаметр_
2
R =3
⇒ d =√( (2R)² +H² )=√( 3² +4² )=√(9 +16 )=√25 =5. * * *
========
4.
H =2πR ; V = πR²H =432
π .
---
2R -?
πR²H =432π ⇔ πR²*(2πR) =432π ⇔ πR³ = 216⇒ R =∛(216/π) =6 / ∛π .
2R=12 / ∛
π .
* * * !
если бы
V = 432
π²
⇒
πR²*(2πR)=432π² ⇔ R³ = 216⇒ R =∛216 =6 .
2R=12 . * * *
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Answers & Comments
Verified answer
1. S_бок =(2πR)*H =(2*π*8 дм)*7 дм =112 π дм².========
2. d =√ ( (2R)² +H² ) =√ ( (2*3)² +4² ) = √ ( 6² +4² ) = √ ( 36 +16 ) =√ 52 =√(4*13) =2√13 (м).
* * * ! если бы диаметр_2R =3
⇒ d =√( (2R)² +H² )=√( 3² +4² )=√(9 +16 )=√25 =5. * * *
========
4. H =2πR ; V = πR²H =432π .
---
2R -?
πR²H =432π ⇔ πR²*(2πR) =432π ⇔ πR³ = 216⇒ R =∛(216/π) =6 / ∛π .
2R=12 / ∛π .
* * * ! если бы V = 432 π²
⇒ πR²*(2πR)=432π² ⇔ R³ = 216⇒ R =∛216 =6 .
2R=12 . * * *