2Me + 2H2O = 2MeOH + H2
15.6/2x = 4.48/22.4
2x = (15.6*22.4)/4.48 = 78
==> x = 39 г/моль
Me = K
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2Me + 2H2O = 2MeOH + H2
15.6/2x = 4.48/22.4
2x = (15.6*22.4)/4.48 = 78
==> x = 39 г/моль
Me = K