Ответ:
Объяснение:
Mr(FeCl2) = 56 + 35,5*2 = 127
W(Fe) = Ar(Fe) *n / Mr(FeCl2) *100% = 56*1 / 127 *100% =44%
W(Cl) = Ar(Cl) *n / Mr(FeCl2) *100% = 35,5*2 / 127 *100% =56%
Mr(SO2) = 32 + 16*2 = 64
W(S) = Ar(S) *n / Mr(SO2) *100% = 32*1 / 64 *100% =50%
W(O) = Ar(O) *n / Mr(SO2) *100% = 16*2 / 64 *100% = 50%
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Ответ:
Объяснение:
Mr(FeCl2) = 56 + 35,5*2 = 127
W(Fe) = Ar(Fe) *n / Mr(FeCl2) *100% = 56*1 / 127 *100% =44%
W(Cl) = Ar(Cl) *n / Mr(FeCl2) *100% = 35,5*2 / 127 *100% =56%
Mr(SO2) = 32 + 16*2 = 64
W(S) = Ar(S) *n / Mr(SO2) *100% = 32*1 / 64 *100% =50%
W(O) = Ar(O) *n / Mr(SO2) *100% = 16*2 / 64 *100% = 50%