Пожалуйста помогите.1 1 3x― - ― - ― 6x-4y 6x+4y 4y2-9x2 . Created by polzyakova. algebra-ru

Пожалуйста помогите.1 1 3x― - ―

June 2022 1 11 Report

Пожалуйста помогите.
1 1    3x
― - ― -   ―
6x-4y 6x+4y 4y2-9x2

Answers & Comments

MissXXX 1/(6x-4y)-1/(6x+4y)-3x/(4y^2-9x^2)=1/(2(3x-2y))-1/(2(3x+2y))-3x/((2y-3x)(2y+3x))=(-2y-3x-2y+3x-6x)/(4y^2-9x^2)=(-4y-6x)/(4x^2-9x^2)=-2(2y+3x)/((2y-3x)(2y+3x))=-2/(2y-3x)

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