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khamova2002
@khamova2002
August 2022
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Пожалуйста помогите!!!
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grunskiy94
2а+2в/9а+9в=2 (а+в)/9(а+в)=2/9
x^2-25/2x-10=(x-5 )(x+5) /2( x-5)=x+5/2
а^3-64/a^2+4a+16=(a-4)(a^2+4a+16)/a^2+4a+16=a-4
x^2+10x+25/x+5=(x+5)^2/x+5=x+5
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Answers & Comments
x^2-25/2x-10=(x-5 )(x+5) /2( x-5)=x+5/2
а^3-64/a^2+4a+16=(a-4)(a^2+4a+16)/a^2+4a+16=a-4
x^2+10x+25/x+5=(x+5)^2/x+5=x+5