пожалуйста, помогите. Created by cowardjoseph. matematika-ru

пожалуйста, помогите...

cowardjoseph @cowardjoseph

July 2022 1 10 Report

пожалуйста, помогите

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NNNLLL54

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$1)\ \ x^2+px+q=0\ \ \Rightarrow \ \ \ \left\{\begin{array}{l}x_1\cdot x_2=q\\x_1+x_2=-p\end{array}\right\\\\\\\left\{\begin{array}{l}-\dfrac{1}{2}\cdot \dfrac{1}{5}=q\\\ -\dfrac{1}{2}+\dfrac{1}{5}=-p\end{array}\right\ \ \left\{\begin{array}{ccc}\ q=-\dfrac{1}{10}\\p=\dfrac{3}{10}\end{array}\right\\\\\\x^2+\dfrac{3}{10}\, x-\dfrac{1}{10}=0\ |\cdot 10\ \ \ \ \Rightarrow \ \ \ 10x^2+3x-1=0$

$2)\ \ y=x^2+3\ \ ,\ \ x_{versh.}=0\ \ ,\ \ \ y\ vozrastaet\ \ x\in [\ 0\, ;+\infty )\\\\y=x^2+6x+9\ \ ,\ \ x_{versh,}=-3\ \ ,\ \ y\ vozrastaet\ \ x\in [\, -3\, ;+\infty )\\\\y=x^2-6x+5\ \ ,\ \ x_{versh,}=3\ \ ,\ \ y\ vozrastaet\ \ x\in [\, 3\, ;+\infty )$

Ответ: A - 3 , Б - 2 , С - 1 .

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