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Mary2111
@Mary2111
August 2022
2
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ПОЖАЛУЙСТА!
Решить уравнения:
(х-2)(х+4)=0;
(х+3.5)(х-7)(х²+9)=0;
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Катєрок
1) ×-2=0 ×+4=0
×=2 ×= -4
2) ×+3,5=0 ×-7=0 ײ+9=0
×= -3,5 ×= 7 ײ= -9
2 votes
Thanks 1
Ручеек
1) (х-2)(х+4)=0
x
²+4x-2x-8=0
x
²+2x-8=0
D=b
²-4ac
D=4+32=36=6
²
x=(-b
±
6)/2
x=2
x=-4
2) (х+3,5)(х-7)(х
²+9)=0
х+3,5=0 х-7=0 х
²+9=0
х=-3,5 х=7 х
²=-9
0 votes
Thanks 0
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Answers & Comments
×=2 ×= -4
2) ×+3,5=0 ×-7=0 ײ+9=0
×= -3,5 ×= 7 ײ= -9
x²+4x-2x-8=0
x²+2x-8=0
D=b²-4ac
D=4+32=36=6²
x=(-b±6)/2
x=2
x=-4
2) (х+3,5)(х-7)(х²+9)=0
х+3,5=0 х-7=0 х²+9=0
х=-3,5 х=7 х²=-9