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Worland
@Worland
July 2022
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Пожалуйста, решите 2 вариант срочно..( любых 3 номера
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Vamdemon
1) по закону сохранения массы
m1=m2, тогда 4/3ПR1^3=N4/3ПR2^3
216=8N
N=27
2)S=Пdh=1700П
3)S=ПRl+ПR^2=55П
4)1/3hП(r1^2+r2^2+r1r2)=1/3hR^2П
R=19
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Answers & Comments
m1=m2, тогда 4/3ПR1^3=N4/3ПR2^3
216=8N
N=27
2)S=Пdh=1700П
3)S=ПRl+ПR^2=55П
4)1/3hП(r1^2+r2^2+r1r2)=1/3hR^2П
R=19