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lenauuuuuuuuuu
@lenauuuuuuuuuu
July 2022
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пожалуйста решите пж....очень надо)
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sedinalana
Verified answer
3(√3/3-tgx)/3(1+√3/3*tgx)=(tgπ/6-tgx)/(1+tgπ/6*tgx)=tg(π/6-x)
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yugolovin
Verified answer
Воспользуемся формулой
(tg α - tg β)/(1+tg α·tg β)=tg(α-β)
Разделим числитель и знаменатель Вашей дроби на 3 (дробь при этом не изменилась) и заменим √3/3 на tg π/6:
(tg π/6 -tg x)/(1+tg π/6·tg x)=tg (π/6-x)
1 votes
Thanks 0
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Answers & Comments
Verified answer
3(√3/3-tgx)/3(1+√3/3*tgx)=(tgπ/6-tgx)/(1+tgπ/6*tgx)=tg(π/6-x)Verified answer
Воспользуемся формулой(tg α - tg β)/(1+tg α·tg β)=tg(α-β)
Разделим числитель и знаменатель Вашей дроби на 3 (дробь при этом не изменилась) и заменим √3/3 на tg π/6:
(tg π/6 -tg x)/(1+tg π/6·tg x)=tg (π/6-x)