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lyubov3690
@lyubov3690
November 2021
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vladzoloev2
2sin^2x+5cosx=5
2(1-cos^2x)+5cosx=5
2-2cos^2x+5cosx-5=0
-3-2cos^x+5cosx=0
t=cosx
-3-2t^2+5t=0
t=1
t=3/2
Cosx=1
Cosx=3/2
x=2kп, k€Z
Ответ: х=2kп, k€Z
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Answers & Comments
2(1-cos^2x)+5cosx=5
2-2cos^2x+5cosx-5=0
-3-2cos^x+5cosx=0
t=cosx
-3-2t^2+5t=0
t=1
t=3/2
Cosx=1
Cosx=3/2
x=2kп, k€Z
Ответ: х=2kп, k€Z