Пожалуйста, решите уравнение. Created by Duckkfacku44. algebra-ru

Пожалуйста, решите уравнение...

NNNLLL54

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$log_{1/7}\, (3x+4)=-1\ \ ,\ \ \ \ \ \ ODZ:\ x>-\dfrac{4}{3}\ ,\\\\\\3x+4=\Big(\dfrac{1}{7}\Big)^{-1}\\\\\\3x+4=7\\\\3x=3\\\\x=1\in ODZ\\\\Otvet:\ \ x=1\ .$

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yossiraiko

Ответ:

Объяснение:

1/7^(-1) = 3х+4

7 = 3х+4

х = 1

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