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jjadar
@jjadar
July 2022
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nKrynka
Решение
2x³ - x² + 5x + 3 = 0
x = - 1/2
2x³ - x² + 5x + 3 I x + 1/2
-(2x² + x²) 2x² - 2x + 6
- 2x²
+ 5x + 3
-(-2x² - x)
6x + 3
-(6x + 3)
-----------
0
2x³ - x² + 5x + 3 = (x + 1/2)*(
2x² - 2x + 6) =
(2x + 1)*(x² - x + 3)
x
² - x + 3 = 0
D = 1 - 4*1*3 = - 11 < 0
действительных корней нет
Ответ: x = - 1/2
1 votes
Thanks 1
jjadar
спасибо большое тебе
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Answers & Comments
2x³ - x² + 5x + 3 = 0
x = - 1/2
2x³ - x² + 5x + 3 I x + 1/2
-(2x² + x²) 2x² - 2x + 6
- 2x² + 5x + 3
-(-2x² - x)
6x + 3
-(6x + 3)
-----------
0
2x³ - x² + 5x + 3 = (x + 1/2)*(2x² - 2x + 6) = (2x + 1)*(x² - x + 3)
x² - x + 3 = 0
D = 1 - 4*1*3 = - 11 < 0
действительных корней нет
Ответ: x = - 1/2