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Iantina
@Iantina
September 2021
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vicper1957z
Verified answer
A)(x²-(√5 +3)x+3√5)/√(2,5-x) =0, x<2,5
x1,2=((√5+3)+-√(5+6√5+9-12√5))/2= (√5+3+-√(14-6√5)/2, 14-6√5>0
b) (x²-x)²- 5(x²-x)-6=0
y=(x²-x)
y²-5y-6=0
y1,2=(5+-√(25+24))/2=(5+-7)/2
y1=-1,y2=6
x²-x=-1, x²-x+1=0, x1,2=(1+-√(1-4))/2-нет действительных корней
x²-x-6=0, x1,2=(1+-√(1+24))/2=(1+-5)/2
x1=-2, x2=3-ответы
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Answers & Comments
Verified answer
A)(x²-(√5 +3)x+3√5)/√(2,5-x) =0, x<2,5x1,2=((√5+3)+-√(5+6√5+9-12√5))/2= (√5+3+-√(14-6√5)/2, 14-6√5>0
b) (x²-x)²- 5(x²-x)-6=0
y=(x²-x)
y²-5y-6=0
y1,2=(5+-√(25+24))/2=(5+-7)/2
y1=-1,y2=6
x²-x=-1, x²-x+1=0, x1,2=(1+-√(1-4))/2-нет действительных корней
x²-x-6=0, x1,2=(1+-√(1+24))/2=(1+-5)/2
x1=-2, x2=3-ответы