1) lgx < 0
ОДЗ: x > 0
x < 1 ⇒ x ∈ (0; 1)
2)lg(x+1) < -1
ОДЗ: x > -1
x + 1 < 0.1
x < -0.9 ⇒ x ∈ (-1; -0.9)
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Answers & Comments
1) lgx < 0
ОДЗ: x > 0
x < 1 ⇒ x ∈ (0; 1)
2)lg(x+1) < -1
ОДЗ: x > -1
x + 1 < 0.1
x < -0.9 ⇒ x ∈ (-1; -0.9)