Пожалуйста,помогите с решением:
1.(2x-5)(x+7)(x+1)=0
2.(x+2)^2=(x+5)^2
3.(x-1)^2=(2x-3)^2
1.(2x-5)(x+7)(x+1)=0
2.(x+2)^2=(x+5)^2
3.(x-1)^2=(2x-3)^2
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Answers & Comments
2х=5
х1=5÷2=2.5
х+7=0
х2=-7
х+1=0
х3=-1
₩₩₩₩₩₩
х^2+4х+4=х^2+10х+25
х^2+4х-х^2-10х=25-4
-6х=21
х=21÷(-6)
х=-21/6=-7/2=-3.5
₩₩₩₩₩₩
х^2-2х+1=4х^2-12х+9
4х^2-12х+9-х^2+2х-1=0
3х^2-10х+8=0
Д=100-4×3×8=100-96=4
х1=(10-2)/2×3=8/6=4/3=1 1/3
х2=(10+2)/2×3=12÷6=2