Предложите метод синтеза 3-хлорбензойной кислоты C6H5COOH, используя бензол, метанол и любые неорганические вещества. Напишите уравнения используемых реакций и укажите условия их проведения
CH3OH+HCl=CH3Cl+HCl
C6H6+CH3Cl (AlCl3) =C6H5-CH3+HCl
5C6H5-CH3+6KMnO4+9H2SO4=5C6H5-COOH+3K2SO4+6MnSO4+14H2O
C6H5-COOH +HNO3( H2SO4) = C6H4(NO2)-COOH+H2O
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Answers & Comments
CH3OH+HCl=CH3Cl+HCl
C6H6+CH3Cl (AlCl3) =C6H5-CH3+HCl
5C6H5-CH3+6KMnO4+9H2SO4=5C6H5-COOH+3K2SO4+6MnSO4+14H2O
C6H5-COOH +HNO3( H2SO4) = C6H4(NO2)-COOH+H2O
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