Представить квадрат двучлена в виде многочлена:
(5-p)^2
(p+6)^2
(12p^3-5)^2
(13+6d)^2
(15k+2)^2
(11-13a)^2
(1-b)^2
(5-6d^5)^2
(m-5)^2
(12+d)^2
(5d+1)^2
(c^3+4a^2)^2
(a-1)^2
(15k^4+13)^2
(c+7)^2
(5-p)^2
(p+6)^2
(12p^3-5)^2
(13+6d)^2
(15k+2)^2
(11-13a)^2
(1-b)^2
(5-6d^5)^2
(m-5)^2
(12+d)^2
(5d+1)^2
(c^3+4a^2)^2
(a-1)^2
(15k^4+13)^2
(c+7)^2
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Verified answer
(5-p)²=25-10p+p²(p+6)²=p²+12p+36
(12p³-5)²=144p⁶-120p³+25
(13+6d)²=169+156d+36d²
(15k+2)²=225k²+60k+4
(11-13a)²=121-286a+169a²
(1-b)²=1-2b+b²
(5-6d⁵)²=25-60d⁵+36d¹⁰
(m-5)²=m²-10m+25
(12+d)²=144+24d+d²
(5d+1)²=25d²+10d+1
(c³+4a²)²=c⁶+8c³a²+16a⁴
(a-1)²=a²-2a+1
(15k⁴+13)²=225k⁸+390k⁴+169
(c+7)²=c²+14c+49
(p+6)^2=p^2+36+12p
(12p^3-5)^2=144p^6+25-120p^3
(13+6d)^2=169+36d^2+156d
(15k+2)^2=255k^2+4+600k
(1-b)^2=1+b^2-2b