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mydriu
@mydriu
July 2022
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представить в виде многочлена:
(m+4n)^2=?
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Vasily1975
Verified answer
(m+4*n)²=m²+2*m*4*n+(4*n)²=m²+8*m*n+16*n².
10 votes
Thanks 11
Kixcertborn2
Verified answer
(m+4n)²=
Используя правило (a+b)²=a²+2ab+b²
m²+2m*4n+(4n)²=
m²+(2*4)mn+4²n²=
=m²+8mn+16n².
7 votes
Thanks 13
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Answers & Comments
Verified answer
(m+4*n)²=m²+2*m*4*n+(4*n)²=m²+8*m*n+16*n².Verified answer
(m+4n)²=Используя правило (a+b)²=a²+2ab+b²
m²+2m*4n+(4n)²=
m²+(2*4)mn+4²n²=
=m²+8mn+16n².