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karinaa14586
@karinaa14586
August 2021
1
25
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представить в виде степени
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markat
5^n*25*125^k:625=5^n*5²*(5³)^k:5^4=5^n*5²*5^3k*5^(-4)=5^(n+2+3k-4)=5^(n+3k-2)
6^(n+1)*36^(2n-2):6*1296=6^(n+1)*6^2(2n-2)*6^(-1)*6^4=6^(n+1+4n-4-1+4)=6^5n
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6^(n+1)*36^(2n-2):6*1296=6^(n+1)*6^2(2n-2)*6^(-1)*6^4=6^(n+1+4n-4-1+4)=6^5n