Ответ:
(2x+y)²-(x-2y)²=
=(2х+у-х+2у)(2х+у+х-2у)=
=(х+3у)(3х-у)
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Ответ:
(2x+y)²-(x-2y)²=
=(2х+у-х+2у)(2х+у+х-2у)=
=(х+3у)(3х-у)